0=2[2x-(3x-4)]-5(x-4)

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Solution for 0=2[2x-(3x-4)]-5(x-4) equation:


Simplifying
0 = 2[2x + -1(3x + -4)] + -5(x + -4)

Reorder the terms:
0 = 2[2x + -1(-4 + 3x)] + -5(x + -4)
0 = 2[2x + (-4 * -1 + 3x * -1)] + -5(x + -4)
0 = 2[2x + (4 + -3x)] + -5(x + -4)

Reorder the terms:
0 = 2[4 + 2x + -3x] + -5(x + -4)

Combine like terms: 2x + -3x = -1x
0 = 2[4 + -1x] + -5(x + -4)
0 = [4 * 2 + -1x * 2] + -5(x + -4)
0 = [8 + -2x] + -5(x + -4)

Reorder the terms:
0 = 8 + -2x + -5(-4 + x)
0 = 8 + -2x + (-4 * -5 + x * -5)
0 = 8 + -2x + (20 + -5x)

Reorder the terms:
0 = 8 + 20 + -2x + -5x

Combine like terms: 8 + 20 = 28
0 = 28 + -2x + -5x

Combine like terms: -2x + -5x = -7x
0 = 28 + -7x

Solving
0 = 28 + -7x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7x' to each side of the equation.
0 + 7x = 28 + -7x + 7x
Remove the zero:
7x = 28 + -7x + 7x

Combine like terms: -7x + 7x = 0
7x = 28 + 0
7x = 28

Divide each side by '7'.
x = 4

Simplifying
x = 4

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